Your friend is typing his name into a keyboard. Sometimes, when typing a character c, the key might get long pressed, and the character will be typed 1 or more times.

You examine the typed characters of the keyboard. Return True if it is possible that it was your friends name, with some characters (possibly none) being long pressed.

Example 1:
Input: name = "alex", typed = "aaleex"
Output: true
Explanation: ‘a’ and ‘e’ in ‘alex’ were long pressed.

Example 2:
Input: name = "saeed", typed = "ssaaedd"
Output: false
Explanation: ‘e’ must have been pressed twice, but it wasn’t in the typed output.

Example 3:
Input: name = "leelee", typed = "lleeelee"
Output: true

Example 4:
Input: name = "laiden", typed = "laiden"
Output: true
Explanation: It’s not necessary to long press any character.

Constraints:

  • 1 <= name.length <= 1000
  • 1 <= typed.length <= 1000
  • name and typed contain only lowercase English letters.

Solution in python:

class Solution:
    def isLongPressedName(self, name: str, typed: str) -> bool:
        i = 0
        j = 0
        prior = name[0]
        while i < len(name):
            if j == len(typed):
                return False
            if name[i] == typed[j]:
                prior = name[i]
                i += 1
                j += 1
            elif typed[j] == prior:
                j += 1
            else:
                return False
        while j < len(typed):
            if typed[j] != name[-1]:
                return False
            j += 1
        return True
最后修改日期: 2021年2月24日

留言

撰写回覆或留言

发布留言必须填写的电子邮件地址不会公开。