836. Rectangle Overlap-矩形重叠

An axis-aligned rectangle is represented as a list [x1, y1, x2, y2], where (x1, y1) is the coordinate of its bottom-left corner, and (x2, y2) is the coordinate of its top-right corner. Its top and bottom edges are parallel to the X-axis, and its left and right edges are parallel to the Y-axis.

Two rectangles overlap if the area of their intersection is positive. To be clear, two rectangles that only touch at the corner or edges do not overlap.

Given two axis-aligned rectangles rec1 and rec2, return true if they overlap, otherwise return false.

Example 1:
Input: rec1 = [0,0,2,2], rec2 = [1,1,3,3]
Output: true

Example 2:
Input: rec1 = [0,0,1,1], rec2 = [1,0,2,1]
Output: false

Example 3:
Input: rec1 = [0,0,1,1], rec2 = [2,2,3,3]
Output: false

Constraints:

• rect1.length == 4
• rect2.length == 4
• -10^9 <= rec1[i], rec2[i] <= 10^9
• rec1[0] <= rec1[2] and rec1[1] <= rec1[3]
• rec2[0] <= rec2[2] and rec2[1] <= rec2[3]

Solution in python:

class Solution:
    def isRectangleOverlap(self, rec1: List[int], rec2: List[int]) -> bool:
        if rec1[0] == rec1[2] or rec1[1] == rec1[3] or rec2[0] == rec2[2] or rec2[1] == rec2[3]:
            return False
        c1 = (rec1[0]+rec1[2])/2
        r1 = (rec1[1]+rec1[3])/2
        c2 = (rec2[0]+rec2[2])/2
        r2 = (rec2[1]+rec2[3])/2
        w1 = (rec1[2]-rec1[0])/2
        h1 = (rec1[3]-rec1[1])/2
        w2 = (rec2[2]-rec2[0])/2
        h2 = (rec2[3]-rec2[1])/2
        if abs(c1-c2) < (w1+w2) and abs(r1-r2) < (h1+h2):
            return True
        else:
            return False