Given a 2D integer matrix M representing the gray scale of an image, you need to design a smoother to make the gray scale of each cell becomes the average gray scale (rounding down) of all the 8 surrounding cells and itself. If a cell has less than 8 surrounding cells, then use as many as you can.
Example 1:
Input:
[[1,1,1],
[1,0,1],
[1,1,1]]
Output:
[[0, 0, 0],
[0, 0, 0],
[0, 0, 0]]
Explanation:
For the point (0,0), (0,2), (2,0), (2,2): floor(3/4) = floor(0.75) = 0
For the point (0,1), (1,0), (1,2), (2,1): floor(5/6) = floor(0.83333333) = 0
For the point (1,1): floor(8/9) = floor(0.88888889) = 0
Note:
The value in the given matrix is in the range of [0, 255].
The length and width of the given matrix are in the range of [1, 150].
Solution in python:
class Solution:
def imageSmoother(self, M: List[List[int]]) -> List[List[int]]:
result = [[ 0 for i in range(len(M[0]))] for j in range(len(M))]
for i in range(len(M)):
for j in range(len(M[0])):
up = max(i-1, 0)
down = min(i+1, len(M)-1)
left = max(j-1, 0)
right = min(j+1, len(M[0])-1)
temp = 0
for s in range(up, down+1):
for t in range(left, right+1):
temp += M[s][t]
result[i][j] = int(temp/((right-left+1)*(down-up+1)))
return result
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